求u-boot makefile 解析
我们会执行 make all 在编译的时候对应到makefile当中：
则有两个 "all:" 对应点？
第一点：ifeq ($(obj)include/config.mk,$(wildcard $(obj)include/config.mk))
# Include autoconf.mk before config.mk so that the config options are available
# to all top level build files.We need the dummy all: target to prevent the
# dependency target in autoconf.mk.dep from being the default.
all:
sinclude $(obj)include/autoconf.mk.dep
sinclude $(obj)include/autoconf.mk第二点：ALL += $(obj)u-boot.srec $(obj)u-boot.bin $(obj)System.map $(U_BOOT_NAND) $(U_BOOT_ONENAND)
all: $(ALL)求解释，我们到底执行的是哪个 “all ” 目标？
另外，第一个all 目标好像没有依赖项啊？
缺省执行make命令时,会相当于执行第一个目标. 所以第一个all放在最前面,作为第一个目标.这样,当执行make时,就相当于执行了make all.
当有多个相同的目标出现时,会将它们合并在一起. Why not test with $(warning xxxxx)?
It's very simple to get out!
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