PHP如何处理jqGrid发过来的复合查询Json条件？
官方demo里只有一个$where变量，可怎么组合成这个串没有讲。现在需要把传过来的json串filters:
{"groupOp":"OR","rules":[{"field":"area","op":"eq","data":"石家庄"},{"field":"vlanid","op":"eq","data":"4023"},{"field":"vlanid","op":"eq","data":"4024"}],"groups":[{"groupOp":"AND","rules":[{"field":"area","op":"eq","data":"石家庄"},{"field":"vlanyewu","op":"eq","data":" "}],"groups":[]}]}
转化为：
((area = "石家庄" AND vlanyewu = " ") OR area = "石家庄" OR vlanid = "4023" OR vlanid = "4024")
这样就可以放到查询条件里。 本帖最后由 huowz 于 2014-05-11 14:30 编辑
已解决！参考这里：http://bbs.phpchina.com/forum.php?mod=viewthread&tid=192803&page=1#pid1614618。
美中不足就是还不能处理带括号的情况，继续研究。
function _makeCondition($field, $oper, $string){
$condition="";
switch ($oper){
case "eq":
$condition=$field . " " . "=" . " " . "'" . $string . "'";
break;
case "ne":
$condition=$field . " " . "<>" . " " . "'" . $string . "'";
break;
case "lt":
$condition=$field . " " . "<" . " " . "'" . $string . "'";
break;
case "le":
$condition=$field . " " . "<=" . " " . "'" . $string . "'";
break;
case "gt":
$condition=$field . " " . ">" . " " . "'" . $string . "'";
break;
case "ge":
$condition=$field . " " . ">=" . " " . "'" . $string . "'";
break;
case "bw":
$condition="$field"." ". "like ". "'".$string ."%'";
break;
case "ew":
$condition="$field"." ". "like "."'%". $string . "'";
break;
case "cn":
$condition="$field"." ". "like "."'%". $string ."%'";
break;
default:
$condition=$field . " " . $oper . " " . "'" . $string . "'";
break;
}
return $condition;
}
$filters = json_decode($_REQUEST['filters'], true);
$operation = $filters['groupOp'];
$rules = $filters['rules'];
print_r($rules);
foreach ($rules as $rule) {
$field=$rule['field'];
$op=$rule['op'];
$data=iconv('utf-8', 'gb2312', $rule['data']);
$condition=_makeCondition($field,$op,$data);
if($where){
$where=$where.' '.$operation.' '.$condition;
}else{
$where=$condition;
}//end $rules if
}//end $rules foreach
8错啊,楼主...
页:
[1]