关于struct.unpack的用法咨询
baseformat="5s 3x 8s 8s"theline="abcdedfgeghgabcdedfgeghg"
remain=len(theline)-struct.calcsize(baseformat)
fmt="%s,%ds" % (baseformat,remain)
struct.unpack(fmt,theline)
执行报错，提示：error: bad char in struct format 这个是怎么回事
我理解unpack的作用就是将字符串拆分成baseformat的格式，比如5s 3x 8s 8s代表首先5个字节，然后跳过3个，再接着两个8个字节的数据，这样理解对吗
另外看unpack的解释：最后一句话什么意思，string的长度必须和calcsize(fmt)的长度一样？
unpack(fmt, string)
Unpack the string (presumably packed by pack(fmt, ...)) according to the given format. The result
is a tuple even if it contains exactly one item. The string must contain exactly the amount of data required
by the format (len(string) must equal calcsize(fmt)).
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