回复 9# 华小飞_Perl
which one do you like ...
1. one hash only
my %all = (
Gilligan=> { map {$_=>1} @gilligan},
Skipper => { map {$_=>1} @skipper },
Professor => { map {$_=>1} @professor },
);
2. modified some code ...
my %ch_all = map {
my $person = $_;
map { $person => { $_ => 1 } } @{ $all{$person} };
} sort keys %all;
my $person = $_;
$person => { map {$_=>1} @{$all{$person}} };
or combine together
$_ => { map {$_=>1} @{$all{$_}} };
回复 11# jason680
大神就是大神,解决了,谢谢! 7 楼的代码我想说, 将列表转换成 hash 的过程中 key 值相同的情况下 后续的 "value" 会替换先前的哪些 "value". 与 "value" 的类型无关
zhlong8 版主解释的非常详细了.
Jason680 大神的代码简单高效, 的确很厉害!
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