如何把list中有关9的字掉
请问如何把一个list 中有关9的字掉如:A = [‘249’,’9598’,’256.9’]
拿掉后A = [‘24’,’58’,’256’]
b = []
for x in a:
if '.' in x:
_t = re.sub('\.', '', x)
b.append(re.sub('9','',_t))
else:
b.append(re.sub('9','', x))
print(b)
>>>['24', '58', '256'] b = []
for x in a:
if '.' in x:
_t = re.sub('\.', '', x)
b.append(re.sub('9','',_t))
else:
b.append(re.sub('9','', x))
print(b)
>>>['24', '58', '256']
b = []
for x in a:
if '.' in x:
_t = re.sub('\.', '', x)
b.append(re.sub('9','',_t))
else:
b.append(re.sub('9','', x))
print(b)
>>>['24', '58', '256']
b = []
for x in a:
if '.' in x:
_t = re.sub('\.', '', x)
b.append(re.sub('9','',_t))
else:
b.append(re.sub('9','', x))
print(b)
>>>['24', '58', '256']
pemako 谢谢 续上面的问题
如果依次加起来
如4+2 =6
5+8 = 13
2+5+6 = 13
A = [ ‘6’,’13’,’13]
我用map(int,b)
得到
invalid literal for int() with base 10: ''
但用int(map(float,b))
却说could not convert string to float:
所以无法用依次轮询方式去做加减
List A 原先是string 做成数字加减,有法办到吗?
回复 1# Demon
list = [ re.sub(r'9','', s) for s in A ]
回复 1# Demon
list = [ re.sub(r'9','', s) for s in A ]
Perl_Er 谢谢,但续我上面的问题
输出是['24', '58', '256']
如果再作处理依次加起来
如4+2 =6
5+8 = 13
2+5+6 = 13
A = [ ‘6’,’13’,’13]
因为list是string,要如何做加减?