//计算s=1+1/2+1/3—-----+1/100的和
public class Xiti4q4 {
public static void main(String[] args) {
double s = 0;
double i = 1;
do {
s = s + 1/i;
i = i + 1;
} while (i
##########################################
5.计算s=1-2/1+1/3-1/4+...-1/100的和。
//计算s=1-1/2+1/3-1/4+.....-1/100的和
public class Xiti4q5 {
/* 方法一:
public static void main(String[] args) {
double s=0;
double s1=0;
double s2=0;
double i = 1;
do {
s1 = s1 + 1/(2*i-1);
s2 = s2 + 1/(2*i);
i = i + 1;
} while (i
} */
// 方法二:
private double s=0;
public void getsum(){
int j=1;
for (double i=1; i