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标题:
apue 里的源码并没有生成守护进程?
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作者:
beauty2001
时间:
2010-02-19 12:06
标题:
apue 里的源码并没有生成守护进程?
在APUE里提到daemonize,我测试时,并没有生成守护进程,用ps -ajx查看,没有我的守护进程
接着我用GDB调试,发现 if ( (pid = fork()) < 0 )
{
err_quit("%s,can't fork",cmd);
}
else if (pid != 0)
{
exit(0);
}
在第一个fork后就终止了,下面的代码完全没有执行,不知那个高手可帮忙调试一下?
我的QQ21429503,欢迎交迎学习。
#include "fun.h"
void daemonize ( const char *cmd )
{
int i,fd0,fd1,fd2;
pid_t pid;
struct rlimit rl;
struct sigaction sa;
umask(0);
if ( getrlimit(RLIMIT_NOFILE,&rl) < 0 )
{
err_quit("%s: can't get file limit",cmd);
}
if ( (pid = fork()) <0 )
{
err_quit("%s,can't fork",cmd);
}
else if (pid != 0)
{
exit(0);
}
setsid();
sa.sa_handler = SIG_IGN;
sigemptyset(&sa.sa_mask);
sa.sa_flags = 0;
if ( sigaction(SIGHUP,&sa,NULL) < 0 )
{
err_quit("%s: can't ignore SIGHUP");
}
if ( (pid = fork()) < 0 )
{
err_quit("%s,can't fork",cmd);
}
else if (pid != 0)
{
exit(0);
}
if ( chdir("/") < 0 )
{
err_quit("%s: can't change directory to /");
}
if ( rl.rlim_max == RLIM_INFINITY )
{
rl.rlim_max = 1024;
}
for ( i=0;i<rl.rlim_max ;i++ )
{
close(i);
}
fd0 = open("/de/null",O_RDWR);
fd1 = dup(0);
fd2 = dup(0);
openlog(cmd,LOG_CONS,LOG_DAEMON);
if ( fd0 != 0 || fd1 != 0 || fd2 != 0)
{
syslog(LOG_ERR,"unexpected file descriptors %d %d %d",fd0,fd1,fd2);
}
exit(1);
return ;
} /* ----- end of function daemonize ----- */
int main ( int argc, char *argv[] )
{
char *cmd;
if ( (cmd = strrchr(argv[0],'/')) == NULL )
{
cmd = argv[0];
}
else
{
cmd++;
}
daemonize(cmd);
exit(0);
} /* ---------- end of function main ---------- */
复制代码
作者:
babyblue_993
时间:
2010-03-20 09:39
你把pid都打出来吧,看看fork成功没
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