Chinaunix
标题:
awk匹配段落,分别处理
[打印本页]
作者:
Carol
时间:
2018-12-14 16:03
标题:
awk匹配段落,分别处理
本帖最后由 Carol 于 2018-12-14 16:24 编辑
需要处理的文件内容:
<Connector port="8443" protocol="org.apache.coyote.http11.Http11NioProtocol" server="server_name"
maxThreads="150" SSLEnabled="true">
<Certificate certificateKeystoreFile="conf/localhost-rsa.jks"
type="RSA" />
</Connector>
<Connector port="8443" protocol="org.apache.coyote.http11.Http11AprProtocol"
maxThreads="150" SSLEnabled="true" >
<UpgradeProtocol className="org.apache.coyote.http2.Http2Protocol" />
</SSLHostConfig>
我截取了其中一段,想要做的事情是匹配<Connector...>之间的内容,然后对<Connector...>进行修改。
举例:
对于scheme="https"这个变量,如果<Connector...>中存在port="8443",判断是否有scheme="https",如果没有则添加,如果有判断属性值是否是"https",不是的话修改;
如果<Connector...>中不存在port="8443",判断是否有scheme="http",如果没有则添加,如果有判断属性值是否是"http",不是的话修改。
我的方法:
if [ -n "`awk '/<Connector/,/>/' file | grep "scheme"`" ] ;then
sed -i '/scheme/s/"https"/"http"/' file
else
sed -i 's/protocol[[:graph:]]*/& scheme="http" /' file
fi
if [ -z "`awk '/<Connector.*port="8443"/,/>/' file | grep "scheme"`" ] ;then
sed -i 's/[[:space:]]*port="8443"[[:space:]]*/& scheme="https" /' file
else
sed -i '/[[:space:]]*port="8443"[[:space:]]*/s/scheme="http"/scheme="https"/' file
fi
这里有两处错误,一个是awk匹配的是几段<Connector...>,只要其中一段包含"scheme"就会返回为真,其实我是想检查每个<Connector...>;
第二个就是sed -i的部分,限制条件不足,可能会重复添加"scheme"变量。
搜了好多文章也不知道怎么能够逐段检查<Connector...>,还望大神指点!!
作者:
本友会机友会摄友会
时间:
2018-12-17 14:47
提示:
作者被禁止或删除 内容自动屏蔽
作者:
wh7211
时间:
2018-12-17 17:40
本帖最后由 wh7211 于 2018-12-17 17:43 编辑
回复
1#
Carol
cat 1
<Connector port="8443" aaa="111"
bbb="222" ccc="333"
ddd="444"
</Connector>
<Connector port="8443" aaa="111"
bbb="222" ccc="333"
ddd="444" scheme="555"
</Connector>
<Connector port="8444" aaa="111"
bbb="222" ccc="333"
ddd="444"
</Connector>
<Connector port="8444" aaa="111"
bbb="222" ccc="333"
ddd="444" scheme="555"
</Connector>
awk '{a[NR]=$0}/port="8443"/{b=1}match($0,"(scheme=[^ ]+)",c){d=c[1];e=NR}/\/Connector/{if(b&&d){sub(d,"scheme=\042https\042",a[e])}else if(b&&!d){sub("$"," scheme=\042https\042",a[NR-1])}else if(!b&&d){sub(d,"scheme=\042http\042",a[e])}else if(!b&&!d){sub("$"," scheme=\042http\042",a[NR-1])};for(i in a){print a[i]};b=d="";delete a}' 1
<Connector port="8443" aaa="111"
bbb="222" ccc="333"
ddd="444" scheme="https"
</Connector>
<Connector port="8443" aaa="111"
bbb="222" ccc="333"
ddd="444" scheme="https"
</Connector>
<Connector port="8444" aaa="111"
bbb="222" ccc="333"
ddd="444" scheme="http"
</Connector>
<Connector port="8444" aaa="111"
bbb="222" ccc="333"
ddd="444" scheme="http"
</Connector>
复制代码
作者:
Carol
时间:
2018-12-17 19:50
回复
3#
wh7211
太感动了,谢谢大神
作者:
Carol
时间:
2018-12-17 19:54
回复
2#
本友会机友会摄友会
好的,我研究研究py的方法,谢谢!
欢迎光临 Chinaunix (http://bbs.chinaunix.net/)
Powered by Discuz! X3.2