<?php
$arr = array(5 => 1, 12 => 2);
$arr[] = 56; // This is the same as $arr[13] = 56;
// at this point of the script
$arr["x"] = 42; // This adds a new element to
// the array with key "x"
unset($arr[5]); // This removes the element from the array
unset($arr); // This deletes the whole array
?>
Checking 0:
Notice: Undefined index: $i in /path/to/script.html on line 9
Bad:
Good: 1
Notice: Undefined index: $i in /path/to/script.html on line 11
Bad:
Good: 1
Checking 1:
Notice: Undefined index: $i in /path/to/script.html on line 9
Bad:
Good: 2
Notice: Undefined index: $i in /path/to/script.html on line 11
Bad:
Good: 2
// 正确
print $arr['fruit']; // apple
print $arr['veggie']; // carrot
// 不正确。This works but also throws a PHP error of
// level E_NOTICE because of an undefined constant named fruit
//
// Notice: Use of undefined constant fruit - assumed 'fruit' in...
print $arr[fruit]; // apple
// Let's define a constant to demonstrate what's going on. We
// will assign value 'veggie' to a constant named fruit.
define('fruit','veggie');
// Notice the difference now
print $arr['fruit']; // apple
print $arr[fruit]; // carrot
// The following is okay as it's inside a string. Constants are not
// looked for within strings so no E_NOTICE error here
print "Hello $arr[fruit]"; // Hello apple
// With one exception, braces surrounding arrays within strings
// allows constants to be looked for
print "Hello {$arr[fruit]}"; // Hello carrot
print "Hello {$arr['fruit']}"; // Hello apple
// This will not work, results in a parse error such as:
// Parse error: parse error, expecting T_STRING' or T_VARIABLE' or T_NUM_STRING'
// This of course applies to using autoglobals in strings as well
print "Hello $arr['fruit']";
print "Hello $_GET['foo']";
// Concatenation is another option
print "Hello " . $arr['fruit']; // Hello apple
?>
<?php
$error_descriptions[E_ERROR] = "A fatal error has occured";
$error_descriptions[E_WARNING] = "PHP issued a warning";
$error_descriptions[E_NOTICE] = "This is just an informal notice";
?>
注意 E_ERROR 也是个合法的标识符,就和第一个例子中的 bar 一样。但是上一个例子实际上和如下写法是一样的:
<?php
$error_descriptions[1] = "A fatal error has occured";
$error_descriptions[2] = "PHP issued a warning";
$error_descriptions[8] = "This is just an informal notice";
?>
因为 E_ERROR 等于 1,等等。
如同我们在以上例子中解释的那样,$foo[bar] 起作用但其实是错误的。它起作用是因为根据语法的预期,bar 被当成了一个常量表达式。然而,在这个例子中不存在名为 bar 的常量。PHP 就假定你指的是字面上的 bar,也就是字符串 "bar",但你忘记写引号了。
那么为什么这样做不好?
<?php
// fill an array with all items from a directory
$handle = opendir('.');
while (false !== ($file = readdir($handle))) {
$files[] = $file;
}
closedir($handle);
?>
// Some examples to address values in the array above
echo $fruits["holes"][5]; // prints "second"
echo $fruits["fruits"]["a"]; // prints "orange"
unset($fruits["holes"][0]); // remove "first"
// Create a new multi-dimensional array
$juices["apple"]["green"] = "good";
?>
您需要注意数组的赋值总是会涉及到值的拷贝。您需要在复制数组时用指向符号(&)。
<?php
$arr1 = array(2, 3);
$arr2 = $arr1;
$arr2[] = 4; // $arr2 is changed,
// $arr1 is still array(2,3)
$arr3 = &$arr1;
$arr3[] = 4; // now $arr1 and $arr3 are the same
?>