请教一个方法

雨过白鹭洲

#include <stdio.h> int fun1() { printf("call fun1\n"); } int fun2() { printf("call fun2\n"); } int fun3() { printf("call fun3\n"); } int fun4() { printf("call fun4\n"); } int fun5() { printf("call fun5\n"); } typedef int (*fun_t)(); int mask[5] = {1, 2, 16, 8, 4}; fun_t funs[5] = {fun5, fun4, fun1, fun2, fun3}; void test(int num) { &nbsp;&nbsp;&nbsp;&nbsp;int i; &nbsp;&nbsp;&nbsp;&nbsp;for (i = 0; i < 5; i++) &nbsp;&nbsp;&nbsp;&nbsp;{ &nbsp;&nbsp;&nbsp;&nbsp;&nbsp;&nbsp;&nbsp;&nbsp;if ((num & mask[i]) != 0) &nbsp;&nbsp;&nbsp;&nbsp;&nbsp;&nbsp;&nbsp;&nbsp;&nbsp;&nbsp;&nbsp;&nbsp;(*funs[i])(); &nbsp;&nbsp;&nbsp;&nbsp;&nbsp;&nbsp;&nbsp;&nbsp;// fun1, fun2, fun3不重复调用 &nbsp;&nbsp;&nbsp;&nbsp;&nbsp;&nbsp;&nbsp;&nbsp;if (i >= 2 && num >= mask[i]) &nbsp;&nbsp;&nbsp;&nbsp;&nbsp;&nbsp;&nbsp;&nbsp;&nbsp;&nbsp;&nbsp;&nbsp;break; &nbsp;&nbsp;&nbsp;&nbsp;} } int main() { &nbsp;&nbsp;&nbsp;&nbsp;int num; &nbsp;&nbsp;&nbsp;&nbsp;for (num = 0; num < 32; num++) &nbsp;&nbsp;&nbsp;&nbsp;{ &nbsp;&nbsp;&nbsp;&nbsp;&nbsp;&nbsp;&nbsp;&nbsp;printf("num = %d\n", num); &nbsp;&nbsp;&nbsp;&nbsp;&nbsp;&nbsp;&nbsp;&nbsp;test(num); &nbsp;&nbsp;&nbsp;&nbsp;&nbsp;&nbsp;&nbsp;&nbsp;printf("\n\n"); &nbsp;&nbsp;&nbsp;&nbsp;} }

怎么样才叫好的方法呢？

雨过白鹭洲

运行结果

num = 0 num = 1 call fun5 num = 2 call fun4 num = 3 call fun5 call fun4 num = 4 call fun3 num = 5 call fun5 call fun3 num = 6 call fun4 call fun3 num = 7 call fun5 call fun4 call fun3 num = 8 call fun2 num = 9 call fun5 call fun2 num = 10 call fun4 call fun2 num = 11 call fun5 call fun4 call fun2 num = 12 call fun2 num = 13 call fun5 call fun2 num = 14 call fun4 call fun2 num = 15 call fun5 call fun4 call fun2 num = 16 call fun1 num = 17 call fun5 call fun1 num = 18 call fun4 call fun1 num = 19 call fun5 call fun4 call fun1 num = 20 call fun1 num = 21 call fun5 call fun1 num = 22 call fun4 call fun1 num = 23 call fun5 call fun4 call fun1 num = 24 call fun1 num = 25 call fun5 call fun1 num = 26 call fun4 call fun1 num = 27 call fun5 call fun4 call fun1 num = 28 call fun1 num = 29 call fun5 call fun1 num = 30 call fun4 call fun1 num = 31 call fun5 call fun4 call fun1

雨过白鹭洲

如果函数12345调用顺序有影响的话，则使用if elseif else会更直接

雨过白鹭洲

上面这个不错

雨过白鹭洲

忽然觉得表驱动法，也是不错的

回头再研究下《代码大全》表驱动那一章