一件诡异的事情，无法理解，请大神指点

bikkuri

大家好！
我有一个问题向大家请教。
有a和b两个文本文件，两者的区别仅仅在于第二行中的最后一个字母，一个是小写字母o，一个是大写字母A。
[root@betactvdh:/tmp]# cat a
1
2% o
3
4
5
6
[root@betactvdh:/tmp]# cat b
1
2% A
3
4
5
6
[root@betactvdh:/tmp]# diff a b
2c2
< 2% o
---
> 2% A[root@betactvdh:/tmp]# hexdump -C a
00000000  31 0a 32 25 20 6f 0a 33  0a 34 0a 35 0a 36 0a     |1.2% o.3.4.5.6.|
0000000f
[root@betactvdh:/tmp]# hexdump -C b
00000000  31 0a 32 25 20 41 0a 33  0a 34 0a 35 0a 36 0a     |1.2% A.3.4.5.6.|
0000000f
[root@betactvdh:/tmp]#



然后我用同一条awk命令将6行的文本折叠成两行，其中对b文件可以得到期望的结果，但是对a文件的操作却失败了！
[root@betactvdh:/tmp]# cat a|awk '{for(i>0;i<=NR;i++)a=$0}END{for(j=0;3*j+1<i;j++){printf"|";for(k=1;k<=3;k++)printf a[3*j+k]"|";printf"\n"}}'
|1|awk: cmd. line:1: (FILENAME=- FNR=6) fatal: not enough arguments to satisfy format string
        `2% o|'
           ^ ran out for this one
[root@betactvdh:/tmp]# cat b|awk '{for(i>0;i<=NR;i++)a=$0}END{for(j=0;3*j+1<i;j++){printf"|";for(k=1;k<=3;k++)printf a[3*j+k]"|";printf"\n"}}'
|1|2% A|3|
|4|5|6|

1. awk '{for(i>0;i<=NR;i++)a[i]=$0}END{for(j=0;3*j+1<i;j++){printf"|";for(k=1;k<=3;k++)printf a[3*j+k]"|";printf"\n"}}'

复制代码

awk的版本是gawk 4.0.2，算是比较高的版本。
[root@betactvdh:/tmp]# awk --version
GNU Awk 4.0.2
Copyright (C) 1989, 1991-2012 Free Software Foundation.

This program is free software; you can redistribute it and/or modify
it under the terms of the GNU General Public License as published by
the Free Software Foundation; either version 3 of the License, or
(at your option) any later version.

This program is distributed in the hope that it will be useful,
but WITHOUT ANY WARRANTY; without even the implied warranty of
MERCHANTABILITY or FITNESS FOR A PARTICULAR PURPOSE.  See the
GNU General Public License for more details.

You should have received a copy of the GNU General Public License
along with this program. If not, see http://www.gnu.org/licenses/.
[root@betactvdh:/tmp]#

请问为什么会出现这种情况呢？



谢谢大家！

bikkuri

回复 2# cfwyy

谢谢您的指点！