use gcc in shell script

红袖添香

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...

VAR="what_ever"     

gcc -D $VAR -o $VAR

...

红袖添香

原帖由 "kfcn" 发表：
Hi, Red Sleeve or other high hands;

I still have the problem of changing the value of  the variable in the c file. Say, the file is soso.c, the variable is cHANGEABLE,  I want the value of cHANGEAB..........

   


okay, i understand what you want.

there are probably some syntax errors or undefined variables in your C code.

1. there should be a hash before define, i.e.  #define
2. since quesheng is a string, it should be quoted  

try this one, assume it's called soso.c

1. #include <stdio.h>
   
2. 
   
3. #ifndef cHANGEABLE
   
4. #define cHANGEABLE "quesheng"
   
5. #endif
   
6. 
   
7. int main()
   
8. {
   
9.     char* var = cHANGEABLE ;
   
10.     printf("cHANGEABLE is: %s\n", var);
    
11.     return(0);
    
12. }

复制代码

then your script 'changeit' may look like this,

1. if [ x"$1" = x ]; then
   
2.     var="quesheng"
   
3. else
   
4.     var=$1
   
5. fi
   
6. echo "the executable file is: $var"
   
7. gcc -DcHANGEABLE=\"$var\" -o $var soso.c
   

复制代码

tested on Solaris and IRIX,

sleeve@sievert:~[503]$ ./changeit xingle
the executable file is: xingle
sleeve@sievert:~[504]$ ls -l xingle
-rwx------   1 sleeve    other       5875 Jun 27 18:06 xingle
sleeve@sievert:~[505]$ ./xingle
cHANGEABLE is: xingle
sleeve@sievert:~[506]$ ./changeit
the executable file is: quesheng
sleeve@sievert:~[507]$ ./quesheng
cHANGEABLE is: quesheng
sleeve@sievert:~[508]$

hope it helps.