[结贴]继承类的构造函数,为什么不能在初始化列表里面初始化基类成员?

cdsfiui

1. 
   
2. #include<iostream>
   
3. using namespace std;
   
4. struct Base01{
   
5.     int m;
   
6.     Base01():m(2){}
   
7.     void p(){cout<<m<<endl;}
   
8. };
   
9. struct Derived01:public Base01{
   
10.     Derived01():m(3){}
    
11. };
    
12. struct Derived02:virtual public Base01{
    
13.     Derived01():m(4){}
    
14. };
    
15. struct my: Derived01,Derived02{
    
16.     my():m(5){}
    
17. };
    
18. int main(){
    
19.     return 0;
    
20. }
    
21. 
    

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G++编译错误：
TestVirtual.cpp: 在构造函数‘Derived01:erived01()’中:
TestVirtual.cpp:9:17: 错误：类‘Derived01’没有名为‘m’的字段
     Derived01():m(3){}
                 ^


改成Derived01():Base01::m(3){}还是不行。
难道基类成员，就只能在基类的初始化列表里面处理吗?
C++的标准有没有这方面的规定和限制?

folklore

不行， 只能这样：

1. 
   
2. #include<iostream>
   
3. using namespace std;
   
4. struct Base01{
   
5.     int m;
   
6.     Base01([color=Red]int am[/color]):m([color=Red]am[/color]){}
   
7.     void p(){cout<<m<<endl;}
   
8. };
   
9. struct Derived01:public Base01{
   
10.     Derived01():[color=Red]Base01[/color](3){}
    
11. [color=Red]    Derived01(int am):Base01(am);[/color]
    
12. };
    
13. struct Derived02:virtual public Base01{
    
14.     Derived01():Base01(4){}
    
15.     [color=Red]    Derived02(int am):Base01(am);[/color]
    
16. };
    
17. struct my: Derived01,Derived02{
    
18.     my():[color=Red]Derived01(5),Derived02(5)[/color]{}
    
19. };
    
20. int main(){
    
21.     return 0;
    
22. }
    
23. 
    

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folklore

#include<iostream>
using namespace std;
struct Base01{
    int m;
    Base01(int am):m(am){}
    void p(){cout<<m<<endl;}
};
struct Derived01:public Base01{
    Derived01():Base01(3){}
    Derived01(int am):Base01(am);
};
struct Derived02:virtual public Base01{
    Derived01():Base01(4){}
        Derived02(int am):Base01(am);
};
struct my: Derived01,Derived02{
    my():Derived01(5),Derived02(5){}
};
int main(){
    return 0;
}

lxyscls

回复 1# cdsfiui

其实我墙裂建议你给Stanley B. Lippman发个邮件问下为什么