一个用java读取XML文件的简单方法---转

sdwjian

XML文件 book.xml

  Kiran
  Pai
  22


  Bill
  Gates
  46


  Steve
  Jobs
  40

程序输出
Root element of the doc is book
Total no of people: 3
First Name: Kiran
Last Name: Pai
Age: 22
First Name: Bill
Last Name: Gates
Age: 46
First Name: Steve
Last Name: Jobs
Age: 40
程序清单
import java.io.File;
import org.w3c.dom.Document;
import org.w3c.dom.*;
import javax.xml.parsers.DocumentBuilderFactory;
import javax.xml.parsers.DocumentBuilder;
import org.xml.sax.SAXException;
import org.xml.sax.SAXParseException;
public class ReadAndPrintXMLFile{
    public static void main (String argv []){
    try {
            DocumentBuilderFactory docBuilderFactory = DocumentBuilderFactory.newInstance();
            DocumentBuilder docBuilder = docBuilderFactory.newDocumentBuilder();
            Document doc = docBuilder.parse (new File("book.xml"));
            // normalize text redivsentation            
            doc.getDocumentElement ().normalize ();
            System.out.println ("Root element of the doc is " + doc.getDocumentElement().getNodeName());
            NodeList listOfPersons = doc.getElementsByTagName("person");
            int totalPersons = listOfPersons.getLength();
            System.out.println("Total no of people : " + totalPersons);
            for(int s=0; s

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