小数点后2位数排序问题请教！

cnbugs

文件t.txt:
1.1
1.30
1.2
1.31
1.11
3.3
2.0
1.3
1.10

想要的结果是:
1.1
1.2
1.3
1.10
1.11
1.30
1.31
2.0
3.3

用 sort t.txt -n 结果如下：
1.1
1.10
1.11
1.2
1.3
1.30
1.31
2.0
3.3

如何来处理这种情况?

ghp268

1. sort  -k1.1 urfile

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=====看错了==编辑下

1. sort -t. -k2n file

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ghp268

or

1. sort  -k1.3n file

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1. info sort
   
2. 
   
3. `-k POS1[,POS2]'
   
4. `--key=POS1[,POS2]'
   
5.      Specify a sort field that consists of the part of the line between
   
6.      POS1 and POS2 (or the end of the line, if POS2 is omitted),
   
7.      _inclusive_.
   
8. 
   
9.      Each POS has the form `F[.C][OPTS]', where F is the number of the
   
10.      field to use, and C is the number of the first character from the
    
11.      beginning of the field.  Fields and character positions are
    
12.      numbered starting with 1; a character position of zero in POS2
    
13.      indicates the field's last character.  If `.C' is omitted from
    
14.      POS1, it defaults to 1 (the beginning of the field); if omitted
    
15.      from POS2, it defaults to 0 (the end of the field).  OPTS are
    
16.      ordering options, allowing individual keys to be sorted according
    
17.      to different rules; see below for details.  Keys can span multiple
    
18.      fields.
    

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cnbugs

E文资料看不懂，对参数k的理解不知道对不对：
sort  -k1.3n file

1是第1个字段
.3是1-3字符
n等同于 -n ？


谢谢你的代码，文件内容我没贴全，我把文件内容变了一下结果又错了，如下：
2.0
1.1
1.10
1.11
1.2
1.3
3.3
1.30
1.31

ywlscpl

回复 4# cnbugs


    sort -t. -k1,1n -k2,2n file

ghp268

回复 4# cnbugs


    -k1.3 指的是第一个域的第三个字符开始比较
    n指按数字值排序，即-n
   英文资料要多看，man

cnbugs

6楼的说明 加5楼的代码理解了参数的用法。
处理文件成功，感谢！

dibug

看置顶十二篇之 sort