1122333444 -> 11\n22\n333......

1cpuer

112233344455566667777779999999
11
22
333

for sed

reyleon

1. echo 112233344455566667777779999999 | sed 's/\(.\)\(\1\)*/&\n/g'

复制代码

1cpuer

回复 2# reyleon

6神神6

# {2018-03-13 11:08:52} root@localhost:/home/ubuntu/1x
# sed 's/\(.\)\(\1\)*/&\n/g' 1.mo
0
8
:
0
2

11
22
333
444
555
6666
777777
9999999


# {2018-03-13 11:09:04} root@localhost:/home/ubuntu/1x
# cat 1.mo
08:02
112233344455566667777779999999

# {2018-03-13 11:09:20} root@localhost:/home/ubuntu/1x
#
#############08:02 换行了咋回事？

找到解了

# {2018-03-13 11:18:31} root@localhost:/home/ubuntu/1x
# sed 's/\(.\)\(.*\)\1/\n&/g' 1.mo

08:02

11
22
333
444
555
6666
777777
9999999

# {2018-03-13 11:18:58} root@localhost:/home/ubuntu/1x

csccyab

I don't know why this does not work.

echo "1112223444444455555" | awk 'BEGIN {FS=""; b=""} {for (i=1;i<=NF;i++) { if (b="") {b=$i;} else if (b==$i) {b=b$i; print b} else if (b!=$i) { printf "%s\n", b; b=""}}}'

1cpuer

回复 4# csccyab

if (`echo 1`) echo yes ;done
awk 不是很懂

cd_ly

echo 112233344455566667777779999999|egrep -o '(.)\1*'
echo 112233344455566667777779999999|sed -r 's/(.)\1*/&\n/g'
echo 112233344455566667777779999999 | awk -F '' '{for(;++i<=NF{if($i!=$(i+1))$i=$i"\n"}}1' OFS=""