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请问:关于unix硬盘容量计算问题?
系统:SCO5
fdisk 划分磁盘disk分区
+--------------+----------+-----------+---------+---------+---------+
|Partition | Status | Type | Start | End | Size |
+--------------+----------+-----------+---------+---------+---------+
| 1 | Active | UNIX | 1 | 570000 | 570000 |
| 2 | Inactive | UNIX | 570001 | 855000 | 285000 |
| 3 | Inactive | UNIX | 855001 | 1139849 | 284849 |
+--------------+----------+-----------+---------+---------+---------+
Total disk size: 2424030 tracks (256 reserved for masterboot and diagnostics)
硬盘大小(MB)/total tracks=MB/track
注意:
start,end,size的数字单位是track
硬盘参数有柱面Cylinder、磁道Head、扇区Sector
cylinder*head=track
track*sector=block
1block=512b
c*h*s*512=硬盘大小(b) /1024=硬盘大小(kb) /1024=硬盘大小(Mb)
柱面*柱头*扇区=块 1block=512b
理解:
把硬盘想象成:一个从里到外层层铁皮裹住的圆柱体,一层铁皮就是1个柱面;再把铁皮想象成一圈圈上下积压在一起的小圆铁丝环,一圈铁丝环就是1个磁道;再把铁丝环想象成1节节焊在一起的铁条,一小节铁条就是1个扇区
开机信息:/var/adm/messages
device address vector dma comment
---------------------------------------------------------------------------
%disk 0x01F0-0x01F7 14 - type=W0 unit=0 cyls=9506 hds=255 secs=63 |
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