能否把下面的SED语句换成AWK 的IF语句

hbczjzc

sed '1,$s/215103|/63|/g' $1 >$2_dq.txt
mv $2_dq.txt $1
sed '1,$s/215106|/66|/g' $1 >$2_dq.txt
mv $2_dq.txt $1
sed '1,$s/215121|/81|/g' $1 >$2_dq.txt
mv $2_dq.txt $1
sed '1,$s/215122|/82|/g' $1 >$2_dq.txt
mv $2_dq.txt $1
sed '1,$s/215123|/83|/g' $1 >$2_dq.txt
mv $2_dq.txt $1
sed '1,$s/215125|/85|/g' $1 >$2_dq.txt
mv $2_dq.txt $1
sed '1,$s/215128|/88|/g' $1 >$2_dq.txt
mv $2_dq.txt $1
rm $2_dq.txt 2>/dev/null
cat $1 | awk 'BEGIN { FS="|" } { printf("%s|%s|%s|%s|%s|%s|%s|%s|%s|%s|-%.2f|%s|%s|%s|%s|%.2f|%s|%s|%s|%s|%s|%s|%s|%s|%s|%s|%s|%s|%s|%s|%s|%s|%s|%s|%s|%s|%s|%s|%s|%s|%s|%s|%s|%s|%s|n","'$2'","1","21511","0",$1,"2",$2,"000","11000020","2",$9,"0.0","0.0","0.0","0.0",$10,$7," "," ","0",$14,$14,$17,$17,$16,"0.0","0.0","1","0","0","0","0","0.0","0.0","39",$1,"1","1","0","0000000000000"," ","0","SGJZ"," ","3") }' >$2_dq.txt

把下面的语句集成到AWK中
if ( $7 == "215103" ) $7="63";
    else if ( $7 == "215106" ) $7="66";



cat $1 | awk 'BEGIN { FS="|" ; if ( $7 == "215103" ) $7="63"; } { printf(".........
$7个字段不进行付值还是原来的数。

[ 本帖最后由 hbczjzc 于 2005-11-15 11:31 编辑 ]

li2002

怎么把if ( $7 == "215103" ) $7="63"; 放在BEGIN里面？

hbczjzc

原帖由 li2002 于 2005-11-15 11:33 发表
怎么把if ( $7 == "215103" ) $7="63"; 放在BEGIN里面？

呵呵，偶对AWK皮毛而已。应该怎样放啊。

li2002

awk 'BEGIN { FS="|" }{ if ( $7 == "215103" ) $7="63";  printf(".........
放在后面的大括号里

hbczjzc

原帖由 li2002 于 2005-11-15 11:41 发表
awk 'BEGIN { FS="|" }{ if ( $7 == "215103" ) $7="63";  printf(".........
放在后面的大括号里

试过了，好像 $7都变成了空得了，是不是哪有错误啊。$7可以这样付值吗

li2002

把你用awk处理的数据贴出来，和你的awk语句

hbczjzc

awk 'BEGIN { FS="|" }{ if ( $7 == "215103" ) $7="63"; ......

为什么 $7 列变成了空值。
位置参数 $2 文件的文件调用位置参数1中的第7个字段，执行了if ( $7 == "215103" ) $7="63"; 生成的$2_dq.txt 文件第17个字段（调用1文件的第7个字段），而变成了空值，

[ 本帖最后由 hbczjzc 于 2005-11-15 12:06 编辑 ]

hbczjzc

看错文件了程序是  }' >$2_dq.txt

输入到 $2_dq.txt 偶一直看 $2.txt 文件（原文件以存在)

不好意思。哈哈哈