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标题: python字典遍历 [打印本页]

作者: constant_zyh188 时间: 2015-02-27 14:09
标题: python字典遍历
现在有系统api接口
通过浏览器打开以后为下面数据：样例
[ { "appList": [ "AA", "BB", "CC" ], "assetSerialNumber": "C1-ST-6565", "devAdminIP": "1.1.1.1", "devAdminPort": "22", "devCode": "010061371", "devDepartment": "服务", "devName": "CCC-NK-1-371", "devStatus": "CLOSE", "nodeType": "CCABROAD", "serialNum": "PR1310D2007070041" }, { "appList": [ "AA", "BB", "OS", "DD" ], "assetSerialNumber": "C1-ST-6837", "devAdminIP": "2.2.2.2", "devAdminPort": "22", "devCode": "010002372", "devDepartment": "服务", "devName": "aaa-ccK-1-372", "devStatus": "CLOSE", "nodeType": "CCABROAD", "serialNum": "PR1310D2007070155" }

现在想通过python，当执行不一样的参数时，也就是不一样的健，得到不一样的值

例如：
devAdminIP: 会得出上面api内容里所有的ip地址。

作者: constant_zyh188 时间: 2015-02-27 14:44
通过 urlopen打开赋值给以后，print显示
{
"appList":    [
   "AA",
   "BB",
   "CC",
   "DD"
],
"assetSerialNumber": "",
"devAdminIP": "1.1.1.1",
"devAdminPort": "22",
"devCode": "96000713T7",
"devDepartment": "GGG",
"devName": "CCC-LD-1-3T7",
"devStatus": "OPEN",
"nodeType": "MAINLAND",
"serialNum": "3SHJD3X_3"
  },
{
"appList":    [
   "AA",
   "BB",
   "CC",
   "DD"
],
"assetSerialNumber": "",
"devAdminIP": "2.2.2.2",
"devAdminPort": "22",
"devCode": "96000713T7",
"devDepartment": "GGG",
"devName": "CCC-LD-1-3T8",
"devStatus": "OPEN",
"nodeType": "MAINLAND",
"serialNum": "3SHJD3X_4"
  },
.........
.........

作者: goofool 时间: 2015-03-01 15:10
现在不就已经是这样了吗

作者: Linux_manne 时间: 2015-03-02 09:33
就是对 json 的操作啊典型的字典操作吧

作者: anthonyfeng 时间: 2015-03-02 22:17
基本是这样：
      page = urllib.urlopen(url)
      html = page.read()
      dict = json.loads(html)

作者: constant_zyh188 时间: 2015-03-09 14:46
对，我是想建立各种方法，然后提取各个项的值，但是这个文件下来有很多个字典分组，我怎么遍历？

作者: substr函数 时间: 2015-07-18 17:43
基本是这样

作者: howge 时间: 2015-07-20 11:33
已经是json格式了，大锅您还要怎么操作？ help下

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