Chinaunix
标题:
如何将文件名拼接成一个字符串
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作者:
yufeiluo
时间:
2017-03-07 16:28
标题:
如何将文件名拼接成一个字符串
ls /var/www/html/wp
index.php wp-blog-header.php wp-includes wp-signup.php
license.txt wp-comments-post.php wp-links-opml.php wp-trackback.php
readme.html wp-config.php wp-load.php xmlrpc.php
wc wp-config-sample.php wp-login.php
wp-activate.php wp-content wp-mail.php
wp-admin wp-cron.php wp-settings.php
如何将这些输出,用一个空格连接起来,赋值给x.
echo $x 将输出
index.php wp-blog-header.php 等等
作者:
haooooaaa
时间:
2017-03-07 16:31
x=`ls | xargs`
复制代码
作者:
moperyblue
时间:
2017-03-07 16:34
ls /var/www/html/wp|paste -sd' '
复制代码
作者:
yufeiluo
时间:
2017-03-07 17:57
$ x=$(ls /var/www/html/wp|paste -sd' ')
$ echo $x
index.php license.txt readme.html wc wp-activate.php wp-admin wp-blog-header.php wp-comments-post.php wp-config.php wp-config-sample.php wp-content wp-cron.php wp-includes wp-links-opml.php wp-load.php wp-login.php wp-mail.php wp-settings.php wp-signup.php wp-trackback.php xmlrpc.php
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