如何快速确定年份呢

Shell_HAT

1. #!/bin/bash
   
2. time1="Fri Aug 23 11:35:21"
   
3. time2="Mon Sep  2 16:18:09"
   
4. time3="Tue Sep  3 16:06:33"
   
5. time4="Sun Dec  2 16:06:34"
   
6. for((i=1;i<=4;i++)); do
   
7.     for((j=2011;j<=2013;j++)); do
   
8.         str=$(eval echo \$time$i)
   
9.         # echo $str
   
10.         WEEK_DAY=$(date -d "${str:0:10} $j ${str:10}" "+%a")
    
11.         if [ "${str:0:3}" == $WEEK_DAY ]; then
    
12.             echo time$i=\"$(date -d "${str:0:10} $j ${str:10}" "+%Y/%m/%d %T")\"
    
13.             break
    
14.         fi
    
15.     done
    
16. done

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