连续字符20个[-] 球代码

1cpuer

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$ printf "%-20s-\n"
sed 's/.\{20\}/-/'  
echo {1..10} | sed 's/./-/g'
$ str=$(printf "%-60s" "*") & echo "${str// /*}"

https://zhidao.baidu.com/question/518497132777314005.html

o枫叶o飘零

1. python -c 'print "-"*20'

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jason680

回复 1# 1cpuer

$ perl -le '{print "-"x20}'
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$ perl -le '{print "*"x20}'
********************

$ echo "-" | awk '{OFS=$1}NF=20'
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$ echo "*" | awk '{OFS=$1}NF=20'
********************

moperyblue

1. yes -|sed 20q|paste -sd ''

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1. echo|sed ':a;/-\{20\}/q;s/$/-/;ta'

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1. printf '\x2D%.0s' `seq 20`;echo
   
2. printf '%.s-' `seq 20`;echo

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WilliBhamlll

1. printf  '%.0s-' {1..20}

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yebailin

echo "--------------------"   我数了好多次 保证有20个 呵呵

重楼君

1. $ echo ""|awk '{for(i=0;i<20;i++){printf "#"}}END{printf "\n"}'
   
2. ####################

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