◆◆◆◆◆请教：成员函数指针的问题◆◆◆◆◆

yupub

#include <stdio.h>

class CBase {
public:
  int baseFunc() { return 1; }
};
typedef int (CBase::*PFNBASE)();

class CDemo :public CBase {
public:
  int curFunc() {return 2; }
  void demoFunc() {
    PFNBASE p1 = (PFNBASE) &CBase::baseFunc;
    PFNBASE p2 = (PFNBASE) &curFunc;
  }
};

int main() {
  CDemo demo;
  demo.curFunc();
}
//////////////////////////////////////////////
编译时行 PFNBASE p2 = (PFNBASE) &curFunc; 报错如下：
error: ISO C++ forbids taking the address of an unqualified or parenthesized non-static member function to form a pointer to member function. Say `&CDemo::curFunc'

hellomotor

PFNBASE p2 = (PFNBASE) &curFunc;
-----------------------------------------------------
PFNBASE p2 = (PFNBASE) &CDemo::curFunc;

yupub

谢谢！

system888net

:wink: 编成细节很重要...