怎样用printf连续打印n个同样的字符？

wibxy

不用循环打印，怎样用printf连续打印n个同样的字符？如果不行，有没有其它好方法？

204tian

char buf[n+1];
buf[n] = 0;
memset(buf, 'a', n);
printf("%s\n", buf);

wibxy

原帖由 204tian 于 2008-3-13 14:11 发表
char buf[n+1];
buf[n] = 0;
memset(buf, 'a', n);
printf("%s\n", buf);

呵呵，怪我没说明白。
只调整printf的参数能不能实现？

flw

print 'a' x 79;

JohnBull

学过循环吧？

Kallawa

i have seen a beautifull section of code as follows:

/*
1.print number from 1 to 1000
2.No loop,no recursion.
*/
#include<stdio.h>

#define A(x) x;x;x;x;x;x;x;x;x;x;

int main()
{
        int n = 1;
        A(A(A(printf("%d",n++))));
        return 0;
}

i hope it will help with your problem ... ^_^