网页中开头的.*贪婪匹配为什么不成功呢

mattoid

解决了，谢谢楼上，加了个(?s)就可以了 。。
不过还不晓得(?s)是虾米意思

8913845

具体我也不知道，从别人那学来的，呵呵

xiaoyu9805119

可以看官方docs
(?iLmsux)
(One or more letters from the set "i", "L", "m", "s", "u", "x".) The group matches the empty string; the letters set the corresponding flags (re.I, re.L, re.M, re.S, re.U, re.X) for the entire regular expression. This is useful if you wish to include the flags as part of the regular expression, instead of passing a flag argument to the compile() function.
Note that the (?x) flag changes how the expression is parsed. It should be used first in the expression string, or after one or more whitespace characters. If there are non-whitespace characters before the flag, the results are undefined.

?s -> re.S

retuor

参数放错了位置：

1. 
   
2. #!/usr/bin/env python                                                           
   
3. 
   
4. import urllib2
   
5. import re
   
6. 
   
7. url = 'http://www.baidu.com'
   
8. body = urllib2.urlopen( url ).read()
   
9. lastLink = re.compile(u'.*http(.*?)>'.encode('gbk'), re.I|re.S).search(body)
   
10. print lastLink.group(1)
    

复制代码

[quote]
://hi.baidu.com/baidu/ target=_blank title="

mattoid

经xiaoyu9805119在13楼这么一提示，查了下是放错位置了，低级错误-_-!
re.compile(u'.*http(.*?)>'.encode('gbk'), re.I|re.S).search(body)