请问如何取到name=value这种格式的value?

lemboyz

文件内容大概是这样的：
2008-10-07 10:10:08 aaaaa bbbbb ccccc HOST=192.168.0.1
2008-10-07 10:10:18 aaaaa bbbbb HOST=192.168.0.3 cccccc
2008-10-07 10:10:28 aaaaa HOST=192.168.0.2 bbbbb cccccc
2008-10-07 10:10:02 aaaaa bbbbb ccccc HOST=192.168.2.1
2008-10-07 10:11:08 aaaaa bbbbb ccccc HOST=192.168.0.3 ddddddd
2008-10-07 10:10:08 HOST=192.168.3.1 aaaa ccc dddd eeee 1121212

我想取第一、第二字段和HOST=后面的ip地址，结果是
2008-10-07 10:10:08 HOST=192.168.0.1
2008-10-07 10:10:18 HOST=192.168.0.3
2008-10-07 10:10:28 HOST=192.168.0.2
2008-10-07 10:10:02 HOST=192.168.2.1
2008-10-07 10:11:08 HOST=192.168.0.3
2008-10-07 10:10:08 HOST=192.168.3.1

li2002

awk '{printf("%s %s ",$1,$2);for(i=3;i<=NF;i++)if($i~/HOST/){printf("%s\n",$i);break}}'

shaneqi

cat urfile | awk '{for(i=1;i<=NF;i++)if($i ~ "HOST")print ($1" "$2" "$i)}'

ly5066113

sed -r 's/(([^ ]+ ){2}).*(HOST[^ ]+).*/\1\3/'

xwmhmily

原帖由 shaneqi 于 2008-10-7 11:27 发表
cat urfile | awk '{for(i=1;i

这个HOST应该用/ /而不是" "包围

awk '{ for(i=3;i<=NF;i++) if($i ~ /HOST/) printf("%s  %s  %s\n",$1,$2,$i)}' ufile

[ 本帖最后由 xwmhmily 于 2008-10-7 13:56 编辑 ]

lemboyz

原帖由 li2002 于 2008-10-7 11:26 发表
awk '{printf("%s %s ",$1,$2);for(i=3;i

谢谢，很好用。