print

hr_it

print "The aswer is ",5*7,"\n"; $foo = "The aswer is ".5*7."\n"; print $foo;

刚看perl. 运行的时候老提示第2个有错误.

String found where operator expected at test line 5, near "7."\n""
        (Missing operator before "\n"?)

why???

dl0622

把5*7用引号引起来吧，可能原因是.号在前，优先于*号

ynchnluiti

. 连接字符串，也可能是浮点数中的.号。
如果7和.之间加个空格就对了，或者5*7加括号

[ 本帖最后由 ynchnluiti 于 2008-10-25 14:50 编辑 ]

hr_it

谢谢楼上的解答.

khandielas

Suggest you to read "Perl Best Practices". It is really a good book, well-written and very practical.