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// 执行 SQL 查询
mysql_query("drop table if EXISTS union_showdata;");
mysql_query("create table union_showdata
SELECT a.`guid`,
SUBSTRING_INDEX(SUBSTRING_INDEX(a.`referer`,'winkee_ad_medid%3D',-1),'%26',1) as medid
from showdata as a where a.referer like '%vipunion.winkee.net%'
and SUBSTR(a.`addtime`,1,10) =DATE_FORMAT(NOW()-INTERVAL 1 DAY,'%Y-%m-%d')
group by a.guid ;");
$sql = "select * from union_showdata";
$query= iconv("UTF-8","GBK",$sql);
$result = mysql_query($query) or die('Query failed: ' . mysql_error());
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执行时提示union_showdata表不存在。为什么在这里第二个SQL(create table union_showdata.....)不成功呢?
[ 本帖最后由 于仁洁 于 2008-12-1 15:18 编辑 ] |
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