echo 奇怪的输出

chuizx

while [ $num -ge 0 ]
do       
if [ $num -gt 0 ]; then
        echo -n " { \"ip\": "\"$ip\", \"downf\": \"$downf$downfunit\", \"downs\": \"$downs$downsunit\", \
        \"upf\": \"$upf$upfunit\", \"ups\": \"$ups$upsunit\", \"com\": \"$com\" }, "
        fi

        if [ $num -eq 0 ]; then
        echo -n " { \"ip\": "\"$ip\", \"downf\": \"$downf$downfunit\", \"downs\": \"$downs$downsunit\", \
        \"upf\": \"$upf$upfunit\", \"ups\": \"$ups$upsunit\", \"com\": \"$com\" } "
        fi
        num=$(($num-1))
done
输出的结果是
{ "ip": "192.168.0.55", "downf": "6.5MB", "downs": "0.0B/s", "upf": "441.4KB", "ups": "0.0B/s", "com": "4" },
        fi

        if [ 1 -eq 0 ]; then
        echo -n  { "ip": "192.168.0.55", "downf": "6.5MB", "downs": "0.0B/s",   "upf": "441.4KB", "ups": "0.0B/s", "com": "4" }
这里的num值是1，这怎么第2个if打印出来了，高手指点下，谢谢。。

smallstar001

你仔细查查你的qutoes， 多的都有点乱了

ly5066113

引号配对的问题。
太多双引号了，楼主自己检查吧。

smallstar001

echo -n " { \"ip\": "\"$ip\", \"downf\": \"$downf$downfunit\", \"downs\": \"$downs$downsunit\",

         look

chuizx

呵呵  谢谢  结贴！！
{ "ip": "192.168.0.55", "downf": "10.8MB", "downs": "0.0B/s",  "upf": "1.0MB", "ups": "0.0B/s", "com": "6" },  { "ip": "192.168.0.155", "downf": "9.9MB", "downs": "0.0B/s", "upf": "1.8MB", "ups": "0.0B/s", "com": "3" }