能否根据RTTI判断两个类是否有父子关系？

tyc611

如果只需要编译时判断，可以用std::tr1::is_base_of判断两个类是否有继承关系
如果你要实现运行时判断，那是很麻烦的

die

// // relay_test.cpp // ~~~~~~~~~~~~~~~~ // // @author <zhuxueling@pica.com> // @data   2008-12-24 #include<iostream> using namespace std; template< typename L, typename S> class relation{    static long  test(...);    static short test(S&);    static L&    refL(); public:    enum { relay   =( sizeof(test(refL())) == sizeof( short))};    enum { equal   = ( relay && relation<S,L>::relay)};    enum { base_of = ( relay && !relation<S,L>::relay)}; }; class A{}; class B: public A{}; class C: public B{}; class D{}; int main(){    cout<< "B -> A? " << relation<B,A>::base_of <<endl;    cout<< "A -> B? " << relation<A,B>::base_of <<endl;    cout<< "C -> A? " << relation<C,A>::base_of <<endl;    cout<< "A -> C? " << relation<A,C>::base_of <<endl;    cout<< "D -> A? " << relation<D,A>::base_of <<endl;    cout<< "A -> D? " << relation<A,D>::base_of <<endl;    cout<< "A == A? " << relation<A,A>::equal   <<endl;    cout<< "B == A? " << relation<B,A>::equal   <<endl;    cout<< "B == B? " << relation<B,B>::equal   <<endl;    return 0; }

$ ./relya_test
B -> A? 1
A -> B? 0
C -> A? 1
A -> C? 0
D -> A? 0
A -> D? 0
A == A? 1
B == A? 0
B == B? 1

[ 本帖最后由 die 于 2008-12-24 19:56 编辑 ]