问个求时间差的问题

merlin852

let sss = xxxx试试

kvkingdom

[root@localhost ~]# date
Wed Mar  4 19:44:54 CST 2009
[root@localhost ~]# echo 2009-03-04 19:40:50 | awk '{gsub("-"," ",$1);gsub(":"," ",$2);time=$1" "$2;dtime=systime()-mktime(time);if (dtime >= 300){print "+++[",dtime,"seconds] more than  5 minutes"}else{print "+++["dtime,"seconds] less than 5 minutes"}}'
+++[256 seconds] less than 5 minutes
[root@localhost ~]# date
Wed Mar  4 19:45:11 CST 2009
[root@localhost ~]# echo 2009-03-04 19:40:11 | awk '{gsub("-"," ",$1);gsub(":"," ",$2);time=$1" "$2;dtime=systime()-mktime(time);if (dtime >= 300){print "+++[",dtime,"seconds] more than  5 minutes"}else{print "+++["dtime,"seconds] less than 5 minutes"}}'
+++[ 309 seconds] more than  5 minutes
[root@localhost ~]# date
Wed Mar  4 19:45:21 CST 2009

提取出日期时间,AWK处理这两个参数,得到mktime函数所需要的YY MM DD HH MM SS格式.mktime()得到提取出来的时间至1970-01-01 00:00:00的秒数,systime()就是系统当前时间到1970-01-01 00:00:00的秒数了,两个秒数相减,如果大于300秒就是大于五分钟.