想写个脚本，把下面这些文件给改名

airzhu

prod_209040_PSPS88UK_SAE_CF_20090305.txt_1212924.Z
prod_209040_PSPS88UK_SAE_CF_20090312.txt_1219479.Z
prod_209040_PSPS88UK_SAE_CF_20090402.txt_1236630.Z
prod_209040_PSPS88UK_SAE_CF_20090423.txt_1252713.Z
prod_209040_PSPS88UK_SAE_CF_20090514.txt_1269143.Z
prod_209040_PSPS88UK_SAE_CF_20090521.txt_1273267.Z


把以_开头的的数字改了，例如从prod_209040_PSPS88UK_SAE_CF_20090305.txt_1212924.Z改成prod_209040_PSPS88UK_SAE_CF_20090305.txt.Z

haimming

for i in * ;do [[ $i =~ prod_[0-9]*_PSPS88UK_SAE_CF_[0-9]*.txt_[0-9]*.Z ]] &&
mv $i ${i%_*.Z}.Z;done

ywlscpl

1. ls prod*.Z |awk '{v=$0;sub(/_[0-9]+\.Z$/,".Z");system("mv "v" "$0"")}'

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blackold

gsed:

1. \ls|sed 's/\(.*\)_[^.]*\.Z$/mv -i & \1.Z/e'

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not gsed:

1. \ls|sed 's/\(.*\)_[^.]*\.Z$/mv -i & \1.Z/'|sh

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springwind426

1. 
   
2. for f in prod*.txt_[0-9]*.Z;do echo mv $f $(echo $f|sed 's/_[0-9]\+.Z$/.Z/');done;
   

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greendays

ls prod* | xargs  sed -rn 's#(.*txt)_[0-9]+(\.Z)#\1\2#g;p'

[ 本帖最后由 greendays 于 2009-6-10 09:08 编辑 ]

lucash

for i in `ls` ; do  j=$(echo $i | sed 's/_[0-9]*\.Z/\.Z'); mv $i $j; done

blackold

bash:

1. for i in prod*;do mv -i $i ${i%_*}.Z;done

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haimming

不作判断，这样的
prod_dsfds_dsfd.Z
改不改？

blackold

看LZ的意思了。可以修改*(pattern).

我理解LZ的意思，应该是已经得到了要改名的文件列表。

[ 本帖最后由 blackold 于 2009-6-10 11:41 编辑 ]