匹配相关求助 [解决]

cearo

[root@test-10-152 data]# awk '{sub(/[0-9]+/,"",$2);print}' test
0001|20081223efskjfdj|EREADFASDLKJCV
0002|20081208djfksdaa|JDKFJALSDJFsddf
0003|20081208efskjfdj|EREADFASDLKJCV
0004|20081211djfksdaa1234|JDKFJALSDJFsddf

我想要的效果是
0001|efskjfdj|EREADFASDLKJCV
0002|djfksdaa|JDKFJALSDJFsddf
0003|efskjfdj|EREADFASDLKJCV
0004|djfksdaa1234|JDKFJALSDJFsddf

已解决
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新问题

0001|20081223efskjfdj|EREADFASDLKJCV
0002|20081208djfksdaa|JDKFJALSDJFsddf
0003|20081208efskjfdj|EREADFASDLKJCV
0004|20081211djfksdaa1234|JDKFJALSDJFsddf

[root@test-10-152 data]# awk -F"|" '{sub(/[0-9]+/,"",$2);print}' test

0001 efskjfdj EREADFASDLKJCV
0002 djfksdaa JDKFJALSDJFsddf
0003 efskjfdj EREADFASDLKJCV
0004 djfksdaa1234 JDKFJALSDJFsddf

我的分割符号 | 怎么没了,怎么加回去.

6楼已解决
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[ 本帖最后由 cearo 于 2009-7-16 11:18 编辑 ]

fucj

以|作为分割符，把第二段的数字过滤掉

cearo

那应该怎么写呢

cearo

awk -F"[|]" '{sub(/[0-9]+/,"",$2);print}' test
看明白了

xiaobaibbb

awk 'BEGIN{OFS=FS="|"}{print $1,$3}'  test

dolinux

我这个应该可以，但是比较麻烦
awk -F"|" '{printf "%s|", $1;printf "%s|", substr($2,9);printf "%s\n", $3}' test

5楼的没有输出$2
4楼的少了分割符

cearo

牛Bxx 我的第2个问题  你都抢答了..

可恶的

sed 's/|[0-9]\+/|/'

greendays

sed 's/2008[0-9]\+//' urf

kvkingdom

awk 'BEGIN{FS=OFS="|"}{sub(/[0-9]+/,"",$2);print}' input-file