有两个变量，当一个变量的值大于一个特定值后，把两个变量里面对应行输出

fusmou

变量1
active_time=`bpdbjobs |grep -i Act|awk '{print $9}'|grep -v End|awk -F : '{print $1}'`
值为：
01
02
03
04
＝＝＝＝＝＝＝＝＝＝＝＝＝＝＝＝＝＝＝＝＝＝
变量2
policy_name=`bpdbjobs |grep -i Act|awk '{print $4}'|grep -v Status`
值为
h0
h1
h3
h4
==========================================================
结果是当变量1的值大于2时，输出
03 h3
04 h4

ly5066113

paste <(echo "$active_time") <(echo "$policy_name") | awk '$1>2'

ywlscpl

没看懂

wtuter

没看懂,

[2]cat 3
01 h0
02 h1
03 h3
04 h4
[2]
[2]
[2]awk '{a[NR]=$1;b[NR]=$2}{if(substr(a[NR],2,1)>substr(b[NR],2,1));print a[3]" "b[3]}' 3


03 h3
03 h3

这样print没有意义吧

fusmou

原帖由 ly5066113 于 2009-11-25 16:04 发表
paste  

$ cat test1
active_time=`bpdbjobs |grep -i Act|awk '{print $9}'|grep -v End|awk -F : '{print $1}'`
policy_name=`bpdbjobs |grep -i Act|awk '{print $4}'|grep -v Status`
paste <(echo "$active_time") <(echo "$policy_name") | awk '$1>2'
Administrator@stseritcnbu1 ~
$ sh ./test1
./test1: 3: Syntax error: "(" unexpected

ly5066113

$ bash --version
GNU bash, version 2.05b.0(1)-release (i386-redhat-linux-gnu)
Copyright (C) 2002 Free Software Foundation, Inc.

fusmou

原帖由 ly5066113 于 2009-11-25 16:22 发表
$ bash --version
GNU bash, version 2.05b.0(1)-release (i386-redhat-linux-gnu)
Copyright (C) 2002 Free Software Foundation, Inc.

$ bash -version
GNU bash, version 2.05b.0(1)-release (i686-pc-cygwin)
Copyright (C) 2002 Free Software Foundation, Inc.

ywlscpl

cygwin

jiangsheng84

我是来学习的！

fusmou

原帖由 ywlscpl 于 2009-11-25 16:30 发表
cygwin

对，把unix的脚本放在上面跑