数组与指针

rainren

指针每次增长的步长怎么算？

#include <stdio.h> int main() { &nbsp;&nbsp;&nbsp;&nbsp;&nbsp;int a[2][3][5]; &nbsp;&nbsp;&nbsp;&nbsp;&nbsp;int (*r)[5]=a[0]; &nbsp;&nbsp;&nbsp;&nbsp;&nbsp;int *t=a[0][0]; &nbsp;&nbsp;&nbsp;&nbsp;&nbsp;printf(" r address: %x\n", r++ ); &nbsp;&nbsp;&nbsp;&nbsp;&nbsp;printf(" next r address: %x\n", r ); &nbsp;&nbsp;&nbsp;&nbsp;&nbsp;printf(" t address: %x\n", t++ ); &nbsp;&nbsp;&nbsp;&nbsp;&nbsp;printf( "next t address: %x\n", t ); &nbsp;&nbsp;&nbsp;&nbsp;&nbsp; &nbsp;&nbsp;&nbsp;&nbsp;&nbsp;return 0; } 运行结果： r前后相差是20, t相差是４, 咋算的？

[ 本帖最后由 rainren 于 2009-11-29 22:56 编辑 ]

mik

int a[5];

int (*p)[5] = &a;
int *q = &a[0];

-----------------------------------------------------
p++  ---> sizeof(a[0]) * 5  == 20
q++  ---> sizeof(int) == 4

rainren

版主的解释明白了！

给后的a[2][3][5]的[3][5]绕晕了！