awk 问题请教

zibingsu

有文件有下面3列数据，

1. BBB00010   sn=75NB3804  67108864
   
2. BBB00011   sn=75NB3904  67108864
   
3. BBB00012   sn=75NB3704  67108864
   
4. AAA00013   sn=75NB3604  67108864
   
5. AAA00014   sn=75NB3504  67108864
   
6. AAA00015   sn=75NB3404  67108864
   
7. AAA00016   sn=75NB3304  67108864
   
8. AAA00017   sn=75NB2804  67108864
   
9. AAA00018   sn=75NB3204  67108864
   
10. AAA00019   sn=75NB3004  67108864
    
11. AAA000110  sn=75NB3104  67108864
    
12. AAA000111  sn=75NB2904  67108864
    
13. AAA000112  sn=75NB2604  67108864
    
14. AAA000113  sn=75NB2704  67108864
    
15. AAA000114  sn=75NB2504  67108864
    
16. AAA000115  sn=75NB2404  67108864
    
17. AAA000116  sn=75NB2304  67108864
    
18. AAA000117  sn=75NB2204  67108864
    
19. AAA000118  sn=75NB2104  67108864
    
20. AAA000119  sn=75NB2004  67108864
    
21. AAA000120  sn=75NB1904  67108864
    
22. AAA000121  sn=75NB1804  67108864
    
23. AAA000122  sn=75NB1704  67108864
    
24. AAA000123  sn=75NB1609  6220288
    
25. AAA000124  sn=75NB1604  67108864
    
26. AAA000125  sn=75NB1509  6220288
    
27. AAA000126  sn=75NB1504  67108864
    
28. AAA000127  sn=75NB1409  6220288
    
29. AAA000128  sn=75NB1404  67108864
    
30. AAA000129  sn=75NB1309  6220288
    
31. AAA000130  sn=75NB1304  67108864
    
32. AAA000131  sn=75NB1204  67108864

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想实现以下效果：
查找第一列是AAA的字符，打印出来前8行，将第2列的sn＝替换为S:,不知道怎么用awk实现，不知道awk怎么处理匹配后的数据,请大家指点下，谢谢！
awk '/^AAA/NR<9{print substr($2,3)}'
         ^^^  ^^^   ^^^^^^^^^^^^^
         匹配    前9行  然后再处理前8行的数据
我想处理后的结果如下.

1. NAME:AAA00013   S:75NB3604
   
2. NAME:AAA00014   S:75NB3504
   
3. NAME:AAA00015   S:75NB3404
   
4. NAME:AAA00016   S:75NB3304
   
5. NAME:AAA00017   S:75NB2804
   
6. NAME:AAA00018   S:75NB3204
   
7. NAME:AAA00019   S:75NB3004
   
8. NAME:AAA000110  S:75NB3104

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ywlscpl

awk '/^AAA/{n++;sub(/sn=/,"S:",$2);print $1,$2}n==8{exit}' file

temp0411

awk '/^AAA/, /^AAA/ {cnt++; sub(/sn=/, "S:", $2); print; if (cnt >= exit }'

[ 本帖最后由 temp0411 于 2009-11-30 12:47 编辑 ]

zibingsu

非常感谢2位，再请问下如果是要打印指定的行，这个应该怎么写，比如打印 10－15行，谢谢！

[ 本帖最后由 zibingsu 于 2009-11-30 16:28 编辑 ]

blackold

NR==10, NR==15

zibingsu

非常感谢快速回复。
awk '/^IBM/NR==5,NR==11{n++;sub(/len=/,"S:",$2);print $1,$2}n==8{exit}'
awk '/^IBM/NR>=5&&NR<=11{n++;sub(/len=/,"S:",$2);print $1,$2}n==8{exit}'
这样好像都不行,继续求教，谢谢！

liaosnet

1. 
   
2. awk 'NR==10,NR==15{if($1~/AAA/){sub(/sn=/,"S:",$2);print $1,$2}}' ufile
   

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blackold

yazi0127

awk '/^AAA/{if(NR>=10&&NR<=15){sub(/sn=/,"S:",$2);print $1,$2}}' file

zibingsu

多谢各位热心回答，aix下的awk太老，只支持NR>=10&&NR<=15。