问一个有关sed匹配模式的话题

blackold

刚才测试了，我上面说的是有错误。

blackold

回复 10# mr_caoke


    这是地址范围。add1,add2

   当add2是行号NUMBER，且NUMBER小于add1，那么只匹配一行。

ghp268

回复 7# mr_caoke


    第三行中有attendance单词包含an。
   在这个模式中前面已经有了出现了一个/an/直到第二行的范围
   sed继续在读入第三行后继续匹配模式，匹配到an,又开始一次范围的匹配

Shell_HAT

9楼解释的很清楚

mr_caoke

回复 13# ghp268


    我来分析一下吧

文件中含有如下行

The honeysuckle band played all night long for only $90.
It was an evening of splendid music and company.
Too bad the disco floor fell through at 23:10.
The local nurse Miss P.Neave was in attendance.

sed -n '/an/,2'p  tmp.sed

第一行有 band ，所以匹配

第二行有 an，所以匹配

第三行既没有an，也不是第2行，所以没匹配。

第四行有attendance，所以匹配

是这样的过程吗？

如果是，那这个应该解释成an或者2，随便匹配哪个都可以

blackold

回复 15# mr_caoke


    LZ强！

Shell_HAT

回复 15# mr_caoke


看看你的理解能否解释这个：

# cat urfile The honeysuckle band played all night long for only $90. Hello world. It was an evening of splendid music and company. Too bad the disco floor fell through at 23:10. The local nurse Miss P.Neave was in attendance. # sed -n '/an/,3'p urfile The honeysuckle band played all night long for only $90. Hello world. It was an evening of splendid music and company. The local nurse Miss P.Neave was in attendance.

ghp268

回复 15# mr_caoke


    addr1,addr2是一个地址范围，标示了起止。你觉得addr1在一个地址范围中需要匹配两次么

blackold

回复 17# Shell_HAT


    应该是DOS的原因，看界面就知道了。这个解释应该八九不离十了。

Shell_HAT

回复 19# blackold


这个不是DOS问题吧，黑哥，我认为9楼正解：

# cat urfile The honeysuckle band played all night long for only $90. Hello world. It was an evening of splendid music and company. Too bad the disco floor fell through at 23:10. The local nurse Miss P.Neave was in attendance. # sed -n '/an/,3'p urfile The honeysuckle band played all night long for only $90. Hello world. It was an evening of splendid music and company. The local nurse Miss P.Neave was in attendance. # uname -a Linux ubuntu 2.6.24-22-generic #1 SMP Mon Nov 24 19:35:06 UTC 2008 x86_64 GNU/Linux