初学perl，写了一个算24点的小程序，请前辈高手指点一下

grshrd49

原来用了递归，有点绕啊

只是一个红薯

哎每次看你的总有惊喜{:3_193:}

rubyish 发表于 2013-06-25 14:34
非常感谢 LZ :

rubyish

只是一个红薯 发表于 2013-06-26 14:01
哎每次看你的总有惊喜

哎~每次看我偷代码是惊喜: {:3_202:}

xiaomm250

送给你我写的代码
http://bbs.chinaunix.net/thread-4297135-1-1.html
有注释,而且程序很容易懂

523066680

xiaomm250 发表于 2019-01-03 11:06
送给你我写的代码http://bbs.chinaunix.net/thread-4297135-1-1.html有注释,而且程序很容易懂

你的代码，测试 1 10000 9998 24，部分结果并不正确：
(1/(10000*9998))+24=24


而且括号和排列组合是写死的，稍微修改一下游戏规则，例如输入6个数字求24点，代码就要大量改动。

xiaomm250

回复 15# 523066680

你走极端了，算24，一般都用扑克牌算的，数字都在1-13之间，怎么可能有那么大的数？

523066680

xiaomm250 发表于 2019-01-15 15:29
回复 15# 523066680 你走极端了，算24，一般都用扑克牌算的，数字都在1-13之间，怎么可能有那么大的数？

所以你满足于扑克牌范围内的实现。
我初学C语言的时候写过一个按分数处理的版本，这样在计算上就比较严谨。
不过我并不满意，因为输出有重复项，比如 (((a*b)*c)*d 和 (d*c)*(b*a) 是等价的，会被并列出来。
后来曾经找到一个在线网站，用javascript实现24点全解无重复的算法，时间长了地址找不到了。

xiaomm250

回复 17# 523066680

没重复也只不过是穷举法罢了。这个就穷举法就能解决的问题，没啥难度
我遇到过穷举法的，大概一千多种情况

xiaomm250

回复 17# 523066680

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穷举法是最好的算法，拿去吧

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回复 19# xiaomm250

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