echo换行符问题

boboskye

# d=`for i in {0..3};do echo -e $i;done`     
# echo $d
0 1 2 3

# for i in {0..3};do echo -e $i;done   
0
1
2
3
何解？变量不能存放换行符？

Shell_HAT

1. d=`for i in {0..3};do echo -e $i;done`
   
2. echo "$d"

复制代码

nxlinux

# d=`for i in {0..3};do echo $i;done`     

echo "$d"

boboskye

回复 2# Shell_HAT


   怎么说呢？

Shell_HAT

回复 4# boboskye


说什么？