求助 字符串计算问题

jiangjingjiu

现在有类似的如下数据,其实是分钟:秒的形式:
14:00
需要输出为14:00--14:10
以此类推,如果是14:50
需要输出为14:50--15:00

我现在的想法是后面先加10,如果是60的话,则前面进一位,但shell语句太多,感觉很麻烦

有谁用awk或sed可以简化一下嘛?

谢谢啊

zzy7186

echo "14:55" | awk -F: '{a=$1;b=$2;a=int(a+(b+10)/60);b=(b+10)%10;printf("%02s:%02s\n",a,b)}'

jiangjingjiu

echo "03:50" | awk -F: '{a=$1;b=$2;a=int(a+(b+10)/60);b=(b+10)%10;printf("%02s:%02s\n",a,b)}'  
04:00

echo "03:40" | awk -F: '{a=$1;b=$2;a=int(a+(b+10)/60);b=(b+10)%10;printf("%02s:%02s\n",a,b)}'  
03:00


有点小问题...

zzy7186

回复 3# jiangjingjiu


    echo "03:40" | awk -F: '{a=$1;b=$2;a=int(a+(b+10)/60);b=(b+10)%60;printf("%02s:%02s\n",a,b)}'
    笔误 把红色部分改成60 应该没问题了

jiangjingjiu

恩,好的,谢谢啊

L_kernel

echo "03:50" | awk -F: '{a=$1;b=$2;a=int(a+(b+10)/60);b=(b+10)%10;printf("%02s:%02s\n",a,b)}'  
04: ...
jiangjingjiu 发表于 2010-12-02 22:46

1. $ echo '14:58' | awk 'BEGIN{FS=":"}{if(($2+10)>=60){minu=$2-50;hour=$1+1}else{minu=$2+10;hour=$1}}{printf "%2s:%2s--%2s:%02d\n",$1,$2,hour,minu}'
   
2. 14:58--15:08
   
3. $ echo '14:52' | awk 'BEGIN{FS=":"}{if(($2+10)>=60){minu=$2-50;hour=$1+1}else{minu=$2+10;hour=$1}}{printf "%2s:%2s--%2s:%02d\n",$1,$2,hour,minu}'
   
4. 14:52--15:02
   
5. $ echo '14:40' | awk 'BEGIN{FS=":"}{if(($2+10)>=60){minu=$2-50;hour=$1+1}else{minu=$2+10;hour=$1}}{printf "%2s:%2s--%2s:%02d\n",$1,$2,hour,minu}'
   
6. 14:40--14:50

复制代码

linyunxian

改别人的考勤？哈哈。

jason680

回复  jiangjingjiu


    echo "03:40" | awk -F: '{a=$1;b=$2;a=int(a+(b+10)/60);b=(b+10)%60;print ...
zzy7186 发表于 2010-12-02 23:01

借来改一下...
# echo "03:55" | awk -F: '{t=$1*60+$2+10;printf("%02d:%02d\n",t/60,t%60)}'
04:05