C++：为什么匹配不上函数？

pmexclusive

1. #include <iostream>
   
2. 
   
3. template <class type> void recycle(type t);
   
4. template <class type> void recycle(type * t);
   
5. 
   
6. int main(void){
   
7.   struct blot {int a; char b[10];};
   
8.   blot ink = {25, "spots"};
   
9. 
   
10.   recycle(&ink);
    
11. 
    
12.   return 0;
    
13. }
    
14. 
    
15. template <class type> void recycle(type t){
    
16.   using namespace std;
    
17.   cout << "this is type t"<< endl;
    
18. }
    
19. 
    
20. template <class type> void recycly(type * t){
    
21.   using namespace std;
    
22.   cout <<"this is type * t" << endl;
    
23. }

复制代码

error: no matching function for call to 'recycle(main()::blot*)'

jhui66

如果第一个的type 被定义成bolt *，编译器怎么办

greensnow

把struct blot {int a; char b[10];};写到main前面去

bruceteen

recycle
recycly

嘿嘿

huxk

rubylc_unix

recycle
recycly

嘿嘿
bruceteen 发表于 2010-12-13 11:01

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