怎么删除一个文件中的空格行？

ringerxyz

就是这一行没有字符，只有空格或者换行符之类的

Shell_HAT

1. sed '/^[ \t]*$/d' urfile

复制代码

ziyunfei

sed '/^\s*$/d' file

昭襄王

就是这一行没有字符，只有空格或者换行符之类的
我理解为非“纯空行”
sed '/^\s\+$/d' file

yinyuemi

tr -s "$" "\n"

zzy7186

awk 'NF!=0{print}' urlfile

nhw_cs

Shell_HAT 发表于 2010-12-31 13:12

    Your solution doesn't always work! Suppose a line contains both space and tab characters, the regular expression doesn't apply to this case.

nhw_cs

The correct solution should be:

sed '/^[^ \t]*$/p' urfile

davidbeckham921

测试了一下，不理解5、9楼的哪里有问题，谁给解释一下
david@ubuntu:~/test/ycx$ cat 1
wincfg_ea.xml dv,jp,ln,va

wincfg_eaa.xml sj,dv,jp,ln,hk,cn,id

wincfg_eab.xml sj,dv,jp,ln,hk
david@ubuntu:~/test/ycx$ sed '/^[^ \t]*$/p' 1
wincfg_ea.xml dv,jp,ln,va


wincfg_eaa.xml sj,dv,jp,ln,hk,cn,id


wincfg_eab.xml sj,dv,jp,ln,hk
david@ubuntu:~/test/ycx$ awk 'NF!=0{print}' 1
wincfg_ea.xml dv,jp,ln,va
wincfg_eaa.xml sj,dv,jp,ln,hk,cn,id
wincfg_eab.xml sj,dv,jp,ln,hk
david@ubuntu:~/test/ycx$ sed '/^\s\+$/d' 1
wincfg_ea.xml dv,jp,ln,va

wincfg_eaa.xml sj,dv,jp,ln,hk,cn,id

wincfg_eab.xml sj,dv,jp,ln,hk
david@ubuntu:~/test/ycx$ sed '/^\s*$/d' 1
wincfg_ea.xml dv,jp,ln,va
wincfg_eaa.xml sj,dv,jp,ln,hk,cn,id
wincfg_eab.xml sj,dv,jp,ln,hk
david@ubuntu:~/test/ycx$ sed '/^[ \t]*$/d' 1
wincfg_ea.xml dv,jp,ln,va
wincfg_eaa.xml sj,dv,jp,ln,hk,cn,id
wincfg_eab.xml sj,dv,jp,ln,hk
david@ubuntu:~/test/ycx$ sed '/^$/d' 1
wincfg_ea.xml dv,jp,ln,va
wincfg_eaa.xml sj,dv,jp,ln,hk,cn,id
wincfg_eab.xml sj,dv,jp,ln,hk