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execlp:
1)如果filename(即第一个参数)中包含了"/",则将其视为路径名,如果不包含,则在环境变量PATH中查看filename
2) 找到filename后便执行该文件,然后将第二个以后的参数当做该文件的argv[0]
execlp ("ls", "-al", (char *)0);
filename arg0 arg1
argv[0] argv[1]
所以没有参数
不过这样子把argv[0] 的内容改掉了, 一般的main函数,argv[0]是可执行文件名,
所以按习惯应该是像 execlp("ls","ls","-al",(char *)0) 这样使用。
/*
* main.c
*/
#include stdio.h>
#include unistd.h>
int
main(int argc, char *argv[])
{
int r;
r = execlp("./hello",
"What's your name?",
"What did you say?",
"What is your name?",
"Oh, call me World.",
(char *)0);
return 0;
}
/*
* hello.c
*/
#include stdio.h>
int
main(int argc, char *argv[])
{
int i;
for (i = 0; i argc; i++) {
printf("%s\n", argv);
}
return 0;
}
/*
* The out put is as the following:
*================================
$ make main hello && ./main
cc -g main.c -o main
cc -g hello.c -o hello
What's your name?
What did you say?
What is your name?
Oh, call me World.
$
*================================
*/
本文来自ChinaUnix博客,如果查看原文请点:http://blog.chinaunix.net/u3/102500/showart_2047364.html |
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