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我在网上下了一个用v4l采集图像的小程序,我编译好了,可以运行,可是采集出来的图像时黑的,没有图像,摄像头和驱动都是好的,因为可以正常使用,肯定是程序有问题,我在检查程序时,有点疑惑,就是在获取channel信息的时候~~请问它这个程序这儿有错吗?程序如下:
#include <stdio.h>
#include <stdlib.h>
#include <sys/types.h>
#include <sys/stat.h>
#include <fcntl.h>
#include <sys/ioctl.h>
#include <sys/mman.h>
#include <errno.h>
#include <linux/videodev.h>
#include <jpeglib.h>
#define WIDTH 320
#define HEIGHT 240
#define V4L_DEVICE "/dev/video0"
main()
{
unsigned char* buf;
int i,j;
int fd;
int re;
struct video_capability vcap;
struct video_channel vc;
struct video_mbuf mbuf;
struct video_mmap mm;
fd = open(V4L_DEVICE, O_RDWR);
if(fd<=0)
{
perror("open");
exit(1);
}
if(ioctl(fd, VIDIOCGCAP, &vcap)<0)
{
perror("VIDIOCGCAP");
exit(1);
}
fprintf(stderr,"Video Capture Device Name : %s\n",vcap.name);
for(i=0;i<vcap.channels;i++)
{
vc.channel = i;
if(ioctl(fd, VIDIOCGCHAN, &vc)<0)
{
perror("VIDIOCGCHAN");
exit(1);
}
fprintf(stderr,"Video Source (%d) Name : %s\n",i, vc.name);
}
vc.channel =1;
vc.norm=1;
if(ioctl(fd, VIDIOCSCHAN, &vc) < 0)
{
perror("VIDIOCSCHAN");
exit(1);
}
if(ioctl(fd, VIDIOCGMBUF, &mbuf) < 0)
{
perror("VIDIOCGMBUF");
exit(1);
}
fprintf(stderr,"the frames number is %d\n",mbuf.frames);
buf = (unsigned char*)mmap(0, mbuf.size, PROT_READ|PROT_WRITE, MAP_SHARED, fd, 0);
if((int)buf < 0)
{
perror("mmap");
exit(1);
}
mm.frame = 0;
mm.height = HEIGHT;
mm.width = WIDTH;
mm.format = VIDEO_PALETTE_RGB24;
if(ioctl(fd, VIDIOCMCAPTURE, &mm)<0)
{
perror("VIDIOCMCAPTURE");
exit(1);
}
if(ioctl(fd, VIDIOCSYNC, &mm.frame)<0)
{
perror("VIDIOCSYNC");
exit(1);
}
if(-1 == (write_jpeg("./pic001.jpeg",buf,75,WIDTH,HEIGHT,0)))
{
printf("write_jpeg error\n");
exit(1);
}
munmap(buf,mbuf.size);
close(fd);
}
我调试程序的时候得知,我的摄像头的vcap.channels是为1的,所以我不知道
vc.channel =1;
vc.norm=1;
是不是错了?是什么意义呢?请高手指点一下 |
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