关于转义字符的几个问题

slowlykiss

main()
{
        char *s = "aaa\x41";
        printf("%s\n",s);
}
输出结果为:aaaA,系统把\x41理解为转义字符'A'了

如果改为:char *s = "aaa\0x41";
输出结果为:aaa,是不是系统把\0x41理解为 \0  x41?因为\0是字符串的结束标志,可是\0x41也可以表示转义字符'A'啊.

如果改为:char *s = "aaa\041";
输出结果为:aaa! 系统把\041理解为八进制转义字符'!',为什么此时又不理解成\0 41了呢?

[ 本帖最后由 slowlykiss 于 2008-10-7 10:58 编辑 ]

meiki05

消灭一下零回复

关于linux的转义，可以看一下man bash中的echo,
\0nnn  the eight-bit character whose value is the octal value nnn (zero to three octal digits)
\nnn   the eight-bit character whose value is the octal value nnn (one to three octal digits)
\xHH   the eight-bit character whose value is the hexadecimal value HH (one or two hex digits)