command line options 疑问？

yalcm

假设有一个如下命令行，请问他的命令行引值是如何传递的？ 谢谢！

$ foo_cmd -c: "abcd efgh ijkl" -r -h  file1.txt <cr>

是这样吗？

argc= 6
argv[0]= "foo_cmd",0
argv[1]= "-c:",0
argv[2]= "abcd efgh ijkl",0
argv[3]= "-r",0
argv[4]= "-h",0
argv[5]= "file1.txt",0

还是这样？

argc= 8
argv[0]= "foo_cmd",0
argv[1]= "-c:",0
argv[2]= "\"abcd",0
argv[3]= "efgh",0
argv[4]= "ijkl\"",0
argv[5]= "-r",0
argv[6]= "-h",0
argv[7]= "file1.txt",0

[ 本帖最后由 yalcm 于 2007-12-9 03:52 编辑 ]

yalcm

Solved.....

Answer is the 1st case.

MMMIX

这种问题自己试下就清楚了。

BTW，答案和你使用的 Shell 是相关的，也即依赖于 Shell 如何解释双引号。