这段C代码会有问题吗？

坤义

......
int scull_c_release(struct inode *inode, struct file *filp)
{
    /*
     * Nothing to do, because the device is persistent.
     * A `real' cloned device should be freed on last close
     */
    MOD_DEC_USE_COUNT;
    return 0;
}


#ifdef LINUX_20

void scull_c_release_20(struct inode *ino, struct file *f)
{
    scull_c_release(ino, f);
}
#define scull_c_release scull_c_release_20

#endif
......

执行宏替换后，会不会造成递归调用啊？那样的话就成死循环了

mq110

这么写有问题.
你可以在定义结构的时候采用.
#ifdef LINUX_20

struct ....
{
.release = scull_c_release_20
}
#else
struct ....
{
.release = scull_c_release
}
#endif
这种写法