echo 显示特殊字符

fans_run

关于显示特殊字符，我们论坛的高手是这样说的：
在打印字符串时要加入八进制字符（ A S C I I相应字符），必须在前面加反斜线，否则s h e l l将其当作普通数字处理。
[mutter@localhost ~] $ echo " This is a copyright 251 sign"
This is a copyright 251 sign
[mutter@localhost ~] $ echo -e " This is a copyright \0373 sign"
This is a copyright
Linux下需要使用\0NNN的八进制的方式才可以把特殊字符copyright的字符显示出来。

但是我执行了“echo -e " This is a copyright \0373 sign"之后，
显示的结果却是：
This is a copyright

ziyunfei

echo -e "This is a copyright \0100 sign"
echo -e "This is a copyright \x40 sign"

ziyunfei

©不在127以内,显示不了好像

ziyunfei

echo -e "This is a copyright \0251 sign"
echo -e "This is a copyright \xA9 sign"

十进制是169

fans_run

哦，多谢了，不在127以内的确实都显示不了，太感谢了。

L_kernel

都可以显示，只是都是乱码。[code]$ echo -e " This is a copyright \0373 sign"
This is a copyright

xiaopan3322

1. xiabao@6P9SN2X ~
   
2. $ uname -a
   
3. CYGWIN_NT-5.1 6P9SN2X 1.7.7(0.230/5/3) 2010-08-31 09:58 i686 Cygwin
   
4. 
   
5. xiabao@6P9SN2X ~
   
6. $ echo -e "This is a copyright \0373 sign"
   
7. This is a copyright gn

复制代码