请教如何将下面换成cookie,而不用session(新手)

软卫甲

[root@Redhat trend]# vi verify.php
<?php
session_start();
if ($user_name !="hello" ||  $login_passwd !="world"
    exit("<center>;Invalid user name or password!</center>;";
else
    $_SESSION['admin_name']=$user_name;
    header("location:index.php";
?>;



[root@Redhat trend]# cat checklogin.php
<?php
session_start();
if ($_SESSION['admin_name']=='')
{
  header("location:login.php";
}
?>;

yb0312

<?
if($user_name !="hello" || $login_passwd !="world"{
         exit("<center>;Invalid user name or password</center>;";
}
else{
           $cookiename=admin_name;
           $values=$user_name;
           setcookie($cookiename,$values); //设置一个名为$cookiename值为$values的cookie
          header("location:index.php";
}
?>;

<?php
$admin_name=$HTTP_COOKIE_VARS["admin_name"];//获得cookie
if (!$admin_name)
{
header("location:login.php";
}
?>;

软卫甲

再次严重感谢谢yb0312 兄       

软卫甲

现在准备将用户换成mysq
努力ing

yb0312

软卫甲

<?php
require_once('sql_con.php');
$user_name=$_POSST['user_name'];
$user_passwd=$_POSST['user_passwd'];
$exec="select * from user_tb where user_name='".$user_name."'";
if ($result=mysql_query($exec))
{
if ($rs=mysql_fetch_object($result))
   {
    if($rs->;user_passwd!=$user_passwd)
    {
     echo "<center>;Invalid  user  password !";
     echo "<br>;";
     echo "<br>;";
     echo "<center>;<a href=login.php>;返回</a>;";
    }
    else
    {
     $cookie_name=login_track;
     $track_value=$user_name;
     setcookie($cookie_name,$track_value);
     header("location:index.php";
    }
   }
else
    {
    echo "<center>;Invalid user name !";
    echo "<br>;";
    echo "<br>;";
    echo "<center>;<a href=login.php>;返回</a>;";
    }
   }
else
   {
    echo "<center>;Database connection fail !";
    echo "<br>;";
    echo "<br>;";
    echo "<center>;<a href=login.php>;返回</a>;";
   }


[参考www.pconline.com.cn]

yb0312

8错，继续努力哦