awk 或者sed处理server_list = array (serv_1,2,3,serv_4,5,8,9)中的编号问题

lionfun

文件com.config中有下面的这一行：
server_list = array (serv_1,2,3,serv_4,5,8,9);

备注：括号中逗号分隔的如1,2,3,serv_4等代表server的编号
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现在有如下需求：
如果我增加了一台server，server的编号为7，那么com.config文件中的"server_list = array (serv_1,2,3,serv_4,5,8,9);"这一行会变成
"server_list = array (serv_1,2,3,serv_4,5,7,8,9);"
如果我增加了一台server，server的编号为serv_6，那么com.config文件中的"server_list = array (serv_1,2,3,serv_4,5,8,9);"这一行会变成
"server_list = array (serv_1,2,3,serv_4,5,serv_6,8,9);"
如果加入的编号原来有则不变，注意编号顺序！
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谢谢！

yinyuemi

回复 1# lionfun


    try:

1. echo 'server_list = array (serv_1,2,3,serv_4,5,8,9);' |\
   
2. awk -v S="7" -F, '{for(i=1;i<NF;i++)if(gensub("serv_","","g",S)<T=gensub(/.*\(|serv_/,"","g",$i)){sub(T,S","T,$i);break}}1' OFS=,
   
3. server_list = array (serv_1,2,3,serv_4,5,7,8,9);
   
4. 
   
5. echo 'server_list = array (serv_1,2,3,serv_4,5,8,9);' |\
   
6. awk -v S="serv_6" -F, '{for(i=1;i<NF;i++)if(gensub("serv_","","g",S)<T=gensub(/.*\(|serv_/,"","g",$i)){sub(T,S","T,$i);break}}1' OFS=,
   
7. server_list = array (serv_1,2,3,serv_4,5,serv_6,8,9);
   

复制代码

lionfun

回复 2# yinyuemi


    谢谢 SS
   如果我还需要传入 S="10" 或者 S="serv_10" 就会变成："server_list = array (serv_1,2,3,serv_4,5,8,9,10);"或者"server_list = array (serv_1,2,3,serv_4,5,8,9,serv_10);"
   如果如果传入S="4" 就原有的"server_list = array (serv_1,2,3,serv_4,5,8,9);"会变成"server_list = array (serv_1,2,3,4,5,8,9);"
   如果我传入S="serv_2" 原有的"server_list = array (serv_1,2,3,serv_4,5,8,9);"就会变成"server_list = array (serv_1,serv_2,3,serv_4,5,8,9);"
   
   那应该怎么实现？

yinyuemi

回复 3# lionfun

try:

1. echo 'server_list = array (serv_1,2,3,serv_4,5,8,9);' |awk -v M=0 -v S="serv_2" -F, '{for(i=1;i<NF;i++)if((gensub("serv_","","g",S)+0)<T=(gensub(/.*\(|serv_/,"","g",$i)+0)){M=1;I=i;break}else{if(gensub("serv_","","g",S)==T=gensub(/.*\(|serv_/,"","g",$i)){M=2;I=i;break}}}{if(M==1){sub(T,S","T,$I)}else{if(M==2){$I=S}else{sub(")",","S"&",$NF)}}}1' OFS=,
   

复制代码

lionfun

回复 4# yinyuemi


    SS 可以！ 谢谢